What are the solutions to the equation 6x^2+1=13 ?

The solutions to the equation 6x^2+1=13 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 6x^2+1=13

The zeros of 6x^2+1=13 are x=sqrt(2),x=-sqrt(2)

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6 x^{2} + 1 = 13

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

6 x^{2} + 1 = 13

Move

1

to the right side

6 x^{2} = 12

Divide both sides by

6

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

\frac{x}{3} = \frac{5}{2}

(\frac{1}{2})^{3} + (\frac{2}{3})^{2}

8 - x = 23

u - 4 = 2

- 2 x - 6 = 0

What are the solutions to the equation 6x^2+1=13 ?
The solutions to the equation 6x^2+1=13 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 6x^2+1=13
The zeros of 6x^2+1=13 are x=sqrt(2),x=-sqrt(2)