What are the solutions to the equation x^2-2x-1=2 ?

The solutions to the equation x^2-2x-1=2 are x=3,x=-1

Find the zeros of x^2-2x-1=2

The zeros of x^2-2x-1=2 are x=3,x=-1

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x^{2} - 2 x - 1 = 2

x = 3, x = - 1

Solution steps

x^{2} - 2 x - 1 = 2

Move

2

to the left side

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

2 x \cdot x^{- \frac{1}{2}}

\frac{10 !}{1 ! 9 !}

3 x^{2} - 3 x - 6

1 3^{\frac{3}{2}}

x \cdot x^{\frac{1}{3}}

What are the solutions to the equation x^2-2x-1=2 ?
The solutions to the equation x^2-2x-1=2 are x=3,x=-1
Find the zeros of x^2-2x-1=2
The zeros of x^2-2x-1=2 are x=3,x=-1