What are the solutions to the equation t^2-25=0 ?

The solutions to the equation t^2-25=0 are t=5,t=-5

Find the zeros of t^2-25=0

The zeros of t^2-25=0 are t=5,t=-5

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t^{2} - 25 = 0

t = 5, t = - 5

Solution steps

t^{2} - 25 = 0

Move

25

to the right side

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

10 x^{2} + 13 x + 4

2^{2} + 5

\frac{4 x - x ^{2}}{ln ( x )}

- 9 = \frac{n}{3}

17 - 2 p = 2 p + 5 + 2 p

What are the solutions to the equation t^2-25=0 ?
The solutions to the equation t^2-25=0 are t=5,t=-5
Find the zeros of t^2-25=0
The zeros of t^2-25=0 are t=5,t=-5