What are the solutions to the equation 2x^2+7x-2=-x^2+2x ?

The solutions to the equation 2x^2+7x-2=-x^2+2x are x= 1/3 ,x=-2

Find the zeros of 2x^2+7x-2=-x^2+2x

The zeros of 2x^2+7x-2=-x^2+2x are x= 1/3 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 7 x - 2 = - x^{2} + 2 x

x = \frac{1}{3}, x = - 2

Solution steps

2 x^{2} + 7 x - 2 = - x^{2} + 2 x

Move

2 x

to the left side

2 x^{2} + 5 x - 2 = - x^{2}

Move

x^{2}

to the left side

3 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 2) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 3}, x_{2} = \frac{- 5 - 7}{2 \cdot 3}

x = \frac{- 5 + 7}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 5 - 7}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

2 (3 x + 1) + 3 x - 2 + x = 2 (4 x - 5) + 2 (2 x - 3)

lo g_{8} (4096)

3 x^{2} + 4 = 13 x

- x (x - 5) (x + 4) > 0

b^{2} - b - 12

What are the solutions to the equation 2x^2+7x-2=-x^2+2x ?
The solutions to the equation 2x^2+7x-2=-x^2+2x are x= 1/3 ,x=-2
Find the zeros of 2x^2+7x-2=-x^2+2x
The zeros of 2x^2+7x-2=-x^2+2x are x= 1/3 ,x=-2