What are the solutions to the equation v^2-8v+15=0 ?

The solutions to the equation v^2-8v+15=0 are v=5,v=3

Find the zeros of v^2-8v+15=0

The zeros of v^2-8v+15=0 are v=5,v=3

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v^{2} - 8 v + 15 = 0

v = 5, v = 3

Solution steps

v^{2} - 8 v + 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

v_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, v_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

v = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

v = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

v = 5, v = 3

6 x = 2 x + 24

∣ x ∣ = x + 5

- \frac{2 x}{( x + 1 ) ^{2} ( x - 1 ) ^{2}} < 0

8 (x + 7) = 104

\frac{4 x ^{3} y ^{2} + 6 x ^{2} y + 3 x}{5 x y}

What are the solutions to the equation v^2-8v+15=0 ?
The solutions to the equation v^2-8v+15=0 are v=5,v=3
Find the zeros of v^2-8v+15=0
The zeros of v^2-8v+15=0 are v=5,v=3