-x^2+x+6<0

Solution

- x^{2} + x + 6 < 0

x < - 2 or x > 3

Interval Notation

(- \infty, - 2) \cup (3, \infty)

Solution steps

- x^{2} + x + 6 < 0

Factor

- x^{2} + x + 6 : - (x + 2) (x - 3)

- (x + 2) (x - 3) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 2) (x - 3)) (- 1) > 0 \cdot (- 1)

Simplify

(x + 2) (x - 3) > 0

Identify the intervals

x < - 2 or x > 3

2 x + 8 = 26

x^{2} + 10 x + 25 = 13

∣ 6.75 - x ∣ < 0.25

- 3 (2 x + 7) \leq \frac{1}{2} x

\frac{x - 3}{3} - 2 < 5 x