What are the solutions to the equation 18-x^2=-20 ?

The solutions to the equation 18-x^2=-20 are x=sqrt(38),x=-sqrt(38)

Find the zeros of 18-x^2=-20

The zeros of 18-x^2=-20 are x=sqrt(38),x=-sqrt(38)

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18 - x^{2} = - 20

x = 38, x = - 38

Decimal Notation

x = 6.16441 \dots, x = - 6.16441 \dots

Solution steps

18 - x^{2} = - 20

Move

18

to the right side

- x^{2} = - 38

Divide both sides by

- 1

x^{2} = 38

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 38, x = - 38

(x + 2) (x - 1) = 3 x + 3 + (7 x^{2} - 9)

\frac{x ^{2} - 4}{x ^{2} - 36} \geq 0

- 7 (- 11 y - 23) + 27 = 24 y + 29

4 y + 2 (2 y - 4) \leq 2 (2 y + 4)

(\frac{x}{y})^{4}

What are the solutions to the equation 18-x^2=-20 ?
The solutions to the equation 18-x^2=-20 are x=sqrt(38),x=-sqrt(38)
Find the zeros of 18-x^2=-20
The zeros of 18-x^2=-20 are x=sqrt(38),x=-sqrt(38)