What is 1/(x-2)>= 6/(x^2+2x-8) ?

The solution to 1/(x-2)>= 6/(x^2+2x-8) is -4 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(x-2)>= 6/(x^2+2x-8)

\frac{1}{x - 2} \geq \frac{6}{x ^{2} + 2 x - 8}

- 4 < x < 2 or x > 2

Interval Notation

(- 4, 2) \cup (2, \infty)

Solution steps

\frac{1}{x - 2} \geq \frac{6}{x ^{2} + 2 x - 8}

Rewrite in standard form

\frac{x - 2}{( x - 2 ) ( x + 4 )} \geq 0

Identify the intervals

- 4 < x < 2 or x > 2

\frac{\frac{1}{3}}{\frac{2 2}{3}}

7.39 - 4.21 a > 3.65

4 (x - 4) (x + 5) < 0

a^{2} + ab + a x + b x

in (\frac{1}{e})

What is 1/(x-2)>= 6/(x^2+2x-8) ?
The solution to 1/(x-2)>= 6/(x^2+2x-8) is -4<x<2\lor x>2