What are the solutions to the equation 6u^2-18u=0 ?

The solutions to the equation 6u^2-18u=0 are u=3,u=0

Find the zeros of 6u^2-18u=0

The zeros of 6u^2-18u=0 are u=3,u=0

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6 u^{2} - 18 u = 0

u = 3, u = 0

Solution steps

6 u^{2} - 18 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 18)^{2} - 4 \cdot 6 \cdot 0 = 18

u_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 6}

Separate the solutions

u_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 6}, u_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 6}

u = \frac{- ( - 18 ) + 18}{2 \cdot 6} : 3

u = \frac{- ( - 18 ) - 18}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

u = 3, u = 0

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What are the solutions to the equation 6u^2-18u=0 ?
The solutions to the equation 6u^2-18u=0 are u=3,u=0
Find the zeros of 6u^2-18u=0
The zeros of 6u^2-18u=0 are u=3,u=0