What are the solutions to the equation x^2+4x+5=0 ?

The solutions to the equation x^2+4x+5=0 are x=-2+i,x=-2-i

Find the zeros of x^2+4x+5=0

The zeros of x^2+4x+5=0 are x=-2+i,x=-2-i

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x^{2} + 4 x + 5 = 0

x = - 2 + i, x = - 2 - i

Solution steps

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

1 \geq - 3 - a

- 3 x = 0

5 x + 2 > 3 x + 10

\frac{2 + 2 i}{3 + 3 i}

7 x^{5} y^{2} - 2 x^{8} y^{6} + 8 x^{3} y^{9}

What are the solutions to the equation x^2+4x+5=0 ?
The solutions to the equation x^2+4x+5=0 are x=-2+i,x=-2-i
Find the zeros of x^2+4x+5=0
The zeros of x^2+4x+5=0 are x=-2+i,x=-2-i