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受欢迎的代数 >

16(3920+6.25x)(1000-x)=125

解答

16 (3920 + 6.25 x) (1000 - x) = 125

解答

x = - \frac{- 37280 + 3728 0 ^{2} + 25087950000}{200}, x = \frac{3728 0 ^{2} + 25087950000 + 37280}{200}

+1

十进制

x = - 627.19923 \dots, x = 999.99923 \dots

求解步骤

16 (3920 + 6.25 x) (1000 - x) = 125

展开

16 (3920 + 6.25 x) (1000 - x) : 62720000 + 37280 x - 100 x^{2}

62720000 + 37280 x - 100 x^{2} = 125

将

125

para o lado esquerdo

- 100 x^{2} + 37280 x + 62719875 = 0

使用求根公式求解

x_{1, 2} = \frac{- 37280 \pm 3728 0 ^{2} - 4 ( - 100 ) \cdot 62719875}{2 ( - 100 )}

3728 0^{2} - 4 (- 100) \cdot 62719875 = 3728 0^{2} + 25087950000

x_{1, 2} = \frac{- 37280 \pm 3728 0 ^{2} + 25087950000}{2 ( - 100 )}

将解分隔开

x_{1} = \frac{- 37280 + 3728 0 ^{2} + 25087950000}{2 ( - 100 )}, x_{2} = \frac{- 37280 - 3728 0 ^{2} + 25087950000}{2 ( - 100 )}

x = \frac{- 37280 + 3728 0 ^{2} + 25087950000}{2 ( - 100 )} : - \frac{- 37280 + 3728 0 ^{2} + 25087950000}{200}

x = \frac{- 37280 - 3728 0 ^{2} + 25087950000}{2 ( - 100 )} : \frac{3728 0 ^{2} + 25087950000 + 37280}{200}

二次方程组的解是:

x = - \frac{- 37280 + 3728 0 ^{2} + 25087950000}{200}, x = \frac{3728 0 ^{2} + 25087950000 + 37280}{200}

作图

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