What are the solutions to the equation 2x^2-24x+80=0 ?

The solutions to the equation 2x^2-24x+80=0 are x=6+2i,x=6-2i

Find the zeros of 2x^2-24x+80=0

The zeros of 2x^2-24x+80=0 are x=6+2i,x=6-2i

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2 x^{2} - 24 x + 80 = 0

x = 6 + 2 i, x = 6 - 2 i

Solution steps

2 x^{2} - 24 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 80}{2 \cdot 2}

Simplify

(- 24)^{2} - 4 \cdot 2 \cdot 80 : 8 i

x_{1, 2} = \frac{- ( - 24 ) \pm 8 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 i}{2 \cdot 2}, x_{2} = \frac{- ( - 24 ) - 8 i}{2 \cdot 2}

x = \frac{- ( - 24 ) + 8 i}{2 \cdot 2} : 6 + 2 i

x = \frac{- ( - 24 ) - 8 i}{2 \cdot 2} : 6 - 2 i

The solutions to the quadratic equation are:

x = 6 + 2 i, x = 6 - 2 i

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643 x + 4600 x^{2} - 1 = 0

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What are the solutions to the equation 2x^2-24x+80=0 ?
The solutions to the equation 2x^2-24x+80=0 are x=6+2i,x=6-2i
Find the zeros of 2x^2-24x+80=0
The zeros of 2x^2-24x+80=0 are x=6+2i,x=6-2i