|x+1|=2

Lösung

∣ x + 1 ∣ = 2

x = - 3 or x = 1

Schritte zur Lösung

∣ x + 1 ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x + 1 = - 2 or x + 1 = 2

x + 1 = - 2 or x + 1 = 2

x = - 3 or x = 1

9 x + 5 + x - 2 = 23

∣ 2 x - 3 ∣ \leq 0.4

s im pl i f y lo g_{\frac{1}{9}} (81)

4 x^{2} - 5 x + 10 = 0

s im pl i f y \frac{2 ^{5}}{3}