What are the solutions to the equation x^2+10x-1=0 ?

The solutions to the equation x^2+10x-1=0 are x=-5+sqrt(26),x=-5-sqrt(26)

Find the zeros of x^2+10x-1=0

The zeros of x^2+10x-1=0 are x=-5+sqrt(26),x=-5-sqrt(26)

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x^{2} + 10 x - 1 = 0

x = - 5 + 26, x = - 5 - 26

Decimal Notation

x = 0.09901 \dots, x = - 10.09901 \dots

Solution steps

x^{2} + 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 1) = 226

x_{1, 2} = \frac{- 10 \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 26}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 26}{2 \cdot 1}

x = \frac{- 10 + 2 26}{2 \cdot 1} : - 5 + 26

x = \frac{- 10 - 2 26}{2 \cdot 1} : - 5 - 26

The solutions to the quadratic equation are:

x = - 5 + 26, x = - 5 - 26

\frac{2 ^{x + 1}}{2 ^{x}}

- 3 \cdot 4

\frac{8}{30}

- 310 - 340

16 x + 90 + 24 x + 10 = 180

What are the solutions to the equation x^2+10x-1=0 ?
The solutions to the equation x^2+10x-1=0 are x=-5+sqrt(26),x=-5-sqrt(26)
Find the zeros of x^2+10x-1=0
The zeros of x^2+10x-1=0 are x=-5+sqrt(26),x=-5-sqrt(26)