What are the solutions to the equation x^2-x-14=0 ?

The solutions to the equation x^2-x-14=0 are x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

Find the zeros of x^2-x-14=0

The zeros of x^2-x-14=0 are x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

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x^{2} - x - 14 = 0

x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

Decimal Notation

x = 4.27491 \dots, x = - 3.27491 \dots

Solution steps

x^{2} - x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 14) = 57

x_{1, 2} = \frac{- ( - 1 ) \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 57}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 57}{2 \cdot 1}

x = \frac{- ( - 1 ) + 57}{2 \cdot 1} : \frac{1 + 57}{2}

x = \frac{- ( - 1 ) - 57}{2 \cdot 1} : \frac{1 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

λ^{2} - 4 λ + 5 = 0

3 x^{2} = 2 x + 3

4 x + 34 = 106

2 (\frac{5 - y}{3}) - 3 y = 7

r - 13 = 3

What are the solutions to the equation x^2-x-14=0 ?
The solutions to the equation x^2-x-14=0 are x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2
Find the zeros of x^2-x-14=0
The zeros of x^2-x-14=0 are x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2