What are the solutions to the equation x^2-4x=0 ?

The solutions to the equation x^2-4x=0 are x=4,x=0

Find the zeros of x^2-4x=0

The zeros of x^2-4x=0 are x=4,x=0

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x^{2} - 4 x = 0

x = 4, x = 0

Solution steps

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

5 y^{2} - 2 y - 3 = 0

4 (x - 1)^{2} + \frac{1}{3} = \frac{7}{9}

x^{2} + 10 x - 600 = 0

8 + 8 p \geq - 152

\frac{15 m ^{- 7}}{3 ( m ^{- 2} ) ^{4}}

What are the solutions to the equation x^2-4x=0 ?
The solutions to the equation x^2-4x=0 are x=4,x=0
Find the zeros of x^2-4x=0
The zeros of x^2-4x=0 are x=4,x=0