What is factor x^2+4x-5 ?

The solution to factor x^2+4x-5 is (x-1)(x+5)

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factor x^2+4x-5

factor

x^{2} + 4 x - 5

(x - 1) (x + 5)

Solution steps

x^{2} + 4 x - 5

Break the expression into groups

= (x^{2} - x) + (5 x - 5)

Factor out

x

from

x^{2} - x : x (x - 1)

Factor out

5

from

5 x - 5 : 5 (x - 1)

= x (x - 1) + 5 (x - 1)

Factor out common term

x - 1

= (x - 1) (x + 5)

9 x - 3 \geq 4 (3 x + 3)

4 0^{2} + 3 0^{2}

- 4 x + 1 = - 9 x + 16

12 - 4 x + 24 x^{2} = 0

8^{6}