What are the solutions to the equation -4g^2-68g=172 ?

The solutions to the equation -4g^2-68g=172 are g=-(17+3sqrt(13))/2 ,g=-(17-3sqrt(13))/2

Find the zeros of -4g^2-68g=172

The zeros of -4g^2-68g=172 are g=-(17+3sqrt(13))/2 ,g=-(17-3sqrt(13))/2

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- 4 g^{2} - 68 g = 172

g = - \frac{17 + 3 13}{2}, g = - \frac{17 - 3 13}{2}

Decimal Notation

g = - 13.90832 \dots, g = - 3.09167 \dots

Solution steps

- 4 g^{2} - 68 g = 172

Move

172

to the left side

- 4 g^{2} - 68 g - 172 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 68 ) \pm ( - 68 ) ^{2} - 4 ( - 4 ) ( - 172 )}{2 ( - 4 )}

(- 68)^{2} - 4 (- 4) (- 172) = 1213

g_{1, 2} = \frac{- ( - 68 ) \pm 12 13}{2 ( - 4 )}

Separate the solutions

g_{1} = \frac{- ( - 68 ) + 12 13}{2 ( - 4 )}, g_{2} = \frac{- ( - 68 ) - 12 13}{2 ( - 4 )}

g = \frac{- ( - 68 ) + 12 13}{2 ( - 4 )} : - \frac{17 + 3 13}{2}

g = \frac{- ( - 68 ) - 12 13}{2 ( - 4 )} : - \frac{17 - 3 13}{2}

The solutions to the quadratic equation are:

g = - \frac{17 + 3 13}{2}, g = - \frac{17 - 3 13}{2}

x^{2} - 9 x + 5 = 0

(e^{- 3 x})^{2}

(6 - 2 i) (6 + 2 i)

4 x + 3 (4 x + 7) = 4 (7 x + 3) - 3

7 x^{2} - 2 = - 65

What are the solutions to the equation -4g^2-68g=172 ?
The solutions to the equation -4g^2-68g=172 are g=-(17+3sqrt(13))/2 ,g=-(17-3sqrt(13))/2
Find the zeros of -4g^2-68g=172
The zeros of -4g^2-68g=172 are g=-(17+3sqrt(13))/2 ,g=-(17-3sqrt(13))/2