faktorisieren-x^4+x^3+4x^2-4x

Lösung

faktorisieren

- x^{4} + x^{3} + 4 x^{2} - 4 x

- x (x - 1) (x + 2) (x - 2)

Schritte zur Lösung

- x^{4} + x^{3} + 4 x^{2} - 4 x

Klammere aus

- 1 : - (x^{4} - x^{3} - 4 x^{2} + 4 x)

= - (x^{4} - x^{3} - 4 x^{2} + 4 x)

Faktorisiere

x^{4} - x^{3} - 4 x^{2} + 4 x : x (x - 1) (x + 2) (x - 2)

= - x (x - 1) (x + 2) (x - 2)

0 = x^{2} - 6 x - 7

∣ 7 x - 1 ∣ + 4 \geq 9

(x + 2) (x + 3) = 6

4 x^{2} - 12 x - 16 = 0

y^{2} - y = 6