t^2+7t+12=0

解

t^{2} + 7 t + 12 = 0

t = - 3, t = - 4

解答ステップ

t^{2} + 7 t + 12 = 0

解くとthe二次式

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

t_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

解を分離する

t_{1} = \frac{- 7 + 1}{2 \cdot 1}, t_{2} = \frac{- 7 - 1}{2 \cdot 1}

t = \frac{- 7 + 1}{2 \cdot 1} : - 3

t = \frac{- 7 - 1}{2 \cdot 1} : - 4

二次equationの解:

t = - 3, t = - 4