integral from 1 to t of (17)/(x^3)

Lösung

\int_{1}^{t} \frac{17}{x ^{3}} d x

17 (- \frac{1}{2 t ^{2}} + \frac{1}{2})

Schritte zur Lösung

\int_{1}^{t} \frac{17}{x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 17 \cdot \int_{1}^{t} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= 17 [- \frac{1}{2 x ^{2}}]_{1}^{t}

Berechne die Grenzen:

- \frac{1}{2 t ^{2}} + \frac{1}{2}

= 17 (- \frac{1}{2 t ^{2}} + \frac{1}{2})

a re a 3 - \frac{1}{2} x, 3 \leq x \leq 15

\int_{0}^{2} (x + 2 - x^{2}) d x

t a y l or e^{x} + e^{- x}

\int \frac{3}{x ^{2} x ^{2} + 25} d x

x \to 0 lim (2 cos (x))