y^{''}+2y^'+3y=0,y^'(0)=2,y(0)=1

Lösung

y^{^{''}} + 2 y^{^{'}} + 3 y = 0, y^{^{'}} (0) = 2, y (0) = 1

y = e^{- t} (cos (2 t) + \frac{3}{2} sin (2 t))

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = e^{- t} (cos (2 t) + \frac{3}{2} sin (2 t))

y = e^{- t} (cos (2 t) + \frac{3}{2} sin (2 t))

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