3xy^'-2y=x^3y^{-2}

Lösung

3 x y^{^{'}} - 2 y = x^{3} y^{- 2}

y = 3 x^{3} + c_{1} x^{2}

Schritte zur Lösung

3 x y^{'} (x) - 2 y = x^{3} y^{- 2}

Solve Bernoulli ODE:

y = 3 x^{3} + c_{1} x^{2}

y = 3 x^{3} + c_{1} x^{2}

\frac{\partial}{\partial y} (x (e^{y} + e^{- y}))

\int \frac{- 6 x ^{2}}{( 2 - 2 x ^{3} ) ^{2}} d x

\int sin^{3} (d) x d x

t an g e n t f (x) = (x^{3} - 16 x)^{10}, (4, 0)

\int_{0}^{\frac{π}{3}} cos^{2} (x) d x