What is the limit as t approaches 0 of e^{-6t} ?

The limit as t approaches 0 of e^{-6t} is 1

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limit as t approaches 0 of e^{-6t}

t \to 0 lim (e^{- 6 t})

1

Solution steps

t \to 0 lim (e^{- 6 t})

Plug in the value

t = 0

= e^{- 6 \cdot 0}

Simplify

= 1

\int \frac{x ^{2} - 16}{x ( x + 2 ) ^{3}} d x

\frac{\partial}{\partial x} (- x^{2} + y^{2})

t^{2} y^{^{''}} - 2 y = 3 t^{2} - 1

x \to 0 lim (\frac{( 1 )}{x})

y^{^{'}} = (1 - y) (2 - y)

What is the limit as t approaches 0 of e^{-6t} ?
The limit as t approaches 0 of e^{-6t} is 1