integral of x^2(2x+2/3)

Lösung

\int x^{2} (2 x + \frac{2}{3}) d x

\frac{x ^{4}}{2} + \frac{2 x ^{3}}{9} + C

Schritte zur Lösung

\int x^{2} (2 x + \frac{2}{3}) d x

2 x + \frac{2}{3} = \frac{2}{3} (\frac{2 x}{\frac{2}{3}} + 1)

= \int x^{2} \frac{2}{3} (\frac{2 x}{\frac{2}{3}} + 1) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{3} \cdot \int x^{2} (\frac{2 x}{\frac{2}{3}} + 1) d x

Vereinfache

= \frac{2}{3} \cdot \int x^{2} (3 x + 1) d x

Multipliziere aus

x^{2} (3 x + 1) : 3 x^{3} + x^{2}

= \frac{2}{3} \cdot \int 3 x^{3} + x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{2}{3} (\int 3 x^{3} d x + \int x^{2} d x)

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int x^{2} d x = \frac{x ^{3}}{3}

= \frac{2}{3} (\frac{3 x ^{4}}{4} + \frac{x ^{3}}{3})

Vereinfache

\frac{2}{3} (\frac{3 x ^{4}}{4} + \frac{x ^{3}}{3}) : \frac{x ^{4}}{2} + \frac{2 x ^{3}}{9}

= \frac{x ^{4}}{2} + \frac{2 x ^{3}}{9}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{2} + \frac{2 x ^{3}}{9} + C

t an g e n t y = (x^{3} - 9 x)^{12}, (- 3, 0)

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