derivative f(t)=1.3e^{0.7t}

Lösung

ableitung von

f (t) = 1.3 e^{0.7 t}

0.91 e^{0.7 t}

Schritte zur Lösung

\frac{d}{d t} (1.3 e^{0.7 t})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.3 \frac{d}{d t} (e^{0.7 t})

Wende die Kettenregel an:

e^{0.7 t} \frac{d}{d t} (0.7 t)

= e^{0.7 t} \frac{d}{d t} (0.7 t)

\frac{d}{d t} (0.7 t) = 0.7

= 1.3 e^{0.7 t} \cdot 0.7

Vereinfache

= 0.91 e^{0.7 t}

\int x \cdot e^{1 - x} d x

s im pl i f y (2 x - 5)^{4} (8 x^{2} - 5)^{- 3}

\frac{\partial}{\partial y} (y e^{- x y})

\frac{d}{d x} (ln (\frac{e ^{x}}{1 + e ^{x}}))

\frac{\partial}{\partial x} (ln ((cos (x) y)^{z}))