5y^'-15x^2=0

Lösung

5 y^{^{'}} - 15 x^{2} = 0

y = x^{3} + c_{1}

Schritte zur Lösung

5 y^{'} (x) - 15 x^{2} = 0

Isoliere

y^{'} (x) : y^{'} (x) = 3 x^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

n \to 10 lim ([1 + (\frac{1}{n})]^{n})

\frac{d}{d x} (2 (1 - x)^{- 3})

x \to 0 lim (\frac{5 ^{x} - 4 ^{x}}{x})

d er i v a t i v e \frac{2 x + 3}{3 x + 2}

\int_{0}^{1} \frac{z}{( z ^{2} + 1 ) ^{3}} d z