derivative of 4x^2cos(x+9x)

Lösung

\frac{d}{d x} (4 x^{2} cos (x) + 9 x)

4 (2 x cos (x) - x^{2} sin (x)) + 9

Schritte zur Lösung

\frac{d}{d x} (4 x^{2} cos (x) + 9 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2} cos (x)) + \frac{d}{d x} (9 x)

\frac{d}{d x} (4 x^{2} cos (x)) = 4 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (9 x) = 9

= 4 (2 x cos (x) - x^{2} sin (x)) + 9

\int_{0}^{1} 8 t e^{5 t^{2}} d t

\int \frac{x ^{3}}{3 3 - 2 x ^{2}} d x

x \to - 2 lim (\frac{3 x - 9}{x + 1})

n = 2 \sum \infty \frac{1}{( - 5 ) ^{n}}

n \to + 0 - lim (5 + \frac{4}{n})