inverselaplace 3/((s+1)^2)

Lösung

inverse laplace transformation

\frac{3}{( s + 1 ) ^{2}}

e^{- t} \cdot 3 t

Schritte zur Lösung

L^{- 1} {\frac{3}{( s + 1 ) ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{3}{( s + 1 ) ^{2}} : a = - 1, F (s) = \frac{3}{s ^{2}}

= e^{- t} L^{- 1} {\frac{3}{s ^{2}}}

L^{- 1} {\frac{3}{s ^{2}}} : 3 t

= e^{- t} \cdot 3 t

n = 1 \sum \infty \frac{4 ^{n}}{2 ^{n}}

s l o p e x y - 3 y^{2} = 8, (14, 4)

\int x e^{- x} d x

\frac{d}{d x} (\frac{2 x}{ln ( x )})

\frac{d}{d x} (\frac{x ^{3}}{1 - x ^{3}})