fläche sqrt(x),x-2,0

Lösung

fläche

x, x - 2, 0

\frac{10}{3}

Dezimale

3.33333 \dots

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

x = x - 2 : x = 4

x = 0 : x = 0

x - 2 = 0 : x = 2

= \int_{0}^{2} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{2}^{4} ∣ f_{2} (x) - f_{1} (x) ∣ d x

= \int_{0}^{2} x - 0 d x + \int_{2}^{4} x - 2 - x d x

\int_{0}^{2} x - 0 d x = \frac{4 2}{3}

\int_{2}^{4} x - 2 - x d x = \frac{16 - 4 2}{3} - 2

= \frac{4 2}{3} + \frac{16 - 4 2}{3} - 2

Vereinfache

= \frac{10}{3}

\frac{\partial}{\partial x} (ln (x^{2} - 4 x y + y^{2}))

x \to 0 lim (\frac{4}{17 + x})

\int \frac{1}{( x ^{2} + 9 )} d x

\frac{d}{d x} (x^{2} + x)

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{2}{x ^{4}}) (x + 8 x^{3}))