sum from n=1 to infinity of (1/2)^{1/n}

Lösung

n = 1 \sum \infty (\frac{1}{2})^{\frac{1}{n}}

divergiert

Schritte zur Lösung

n = 1 \sum \infty (\frac{1}{2})^{\frac{1}{n}}

Seriendivergenztest anwenden:

divergiert

= divergiert

\int_{1}^{2} (x + \frac{1}{x})^{2} d x

\frac{\partial}{\partial y} (5 x^{2} - 3 x y + x yz)

x \to \infty lim (- 2 \cdot x)

a re a y = e^{- x}, x = 2, y = 1

\frac{d}{d x} (arccos (\frac{x}{π}))