y^{''}+2y^'+4y=5sin(t)

Lösung

y^{^{''}} + 2 y^{^{'}} + 4 y = 5 sin (t)

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{15}{13} sin (t) - \frac{10}{13} cos (t)

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 4 y = 5 sin (t)

Solve linear ODE:

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{15}{13} sin (t) - \frac{10}{13} cos (t)

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{15}{13} sin (t) - \frac{10}{13} cos (t)

\int (- x^{2} - 3 x + 6)^{2} d x

y^{^{''}} - 5 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

d er i v a t i v e \frac{2 ^{x}}{3 x - 1}

n = 1 \sum \infty \frac{5 n ln ( n )}{6 ^{n}}

d er i v a t i v e \frac{5 + csc ( x )}{9 - csc ( x )}