y^{'''}-8=0

解答

y^{^{'''}} - 8 = 0

y = \frac{4 t ^{3}}{3} + \frac{c _{1} t ^{2}}{2} + c_{2} t + c_{3}

求解步骤

y^{'''} (t) - 8 = 0

整理

y^{'''} (t) : y^{'''} (t) = 8

解

y^{'''} (t) = 8 : y^{''} (t) = 8 t + c_{1}

解

y^{''} (t) = 8 t + c_{1} : y^{'} (t) = 4 t^{2} + c_{1} t + c_{2}

解

y^{'} (t) = 4 t^{2} + c_{1} t + c_{2} : y = \frac{4 t ^{3}}{3} + \frac{c _{1} t ^{2}}{2} + c_{2} t + c_{3}

y = \frac{4 t ^{3}}{3} + \frac{c _{1} t ^{2}}{2} + c_{2} t + c_{3}

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