(\partial)/(\partial x)(-6y^2+12xy)

解答

\frac{\partial}{\partial x} (- 6 y^{2} + 12 x y)

12 y

求解步骤

\frac{\partial}{\partial x} (- 6 y^{2} + 12 x y)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (6 y^{2}) + \frac{\partial}{\partial x} (12 x y)

\frac{\partial}{\partial x} (6 y^{2}) = 0

\frac{\partial}{\partial x} (12 x y) = 12 y

= - 0 + 12 y

化简

= 12 y

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