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受欢迎的微积分 >

tangent sin(5x)+cos(4x)

解答

切线

sin (5 x) + cos (4 x)

解答

y = (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) x + sin (5 a_{0}) + cos (4 a_{0}) - (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) a_{0}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, sin (5 a_{0}) + cos (4 a_{0}))

计算

y = sin (5 x) + cos (4 x)

的斜率:

\frac{d y}{d x} = cos (5 x) \cdot 5 - sin (4 x) \cdot 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4

找到斜率 m=

cos (5 a_{0}) 5 - sin (4 a_{0}) 4

且穿过

(a_{0}, sin (5 a_{0}) + cos (4 a_{0}))

的直线:

y = (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) x + sin (5 a_{0}) + cos (4 a_{0}) - (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) a_{0}

y = (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) x + sin (5 a_{0}) + cos (4 a_{0}) - (cos (5 a_{0}) \cdot 5 - sin (4 a_{0}) \cdot 4) a_{0}

作图

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