derivative of arcsin(2x+arccos(2x))

Lösung

\frac{d}{d x} (arcsin (2 x) + arccos (2 x))

0

Schritte zur Lösung

\frac{d}{d x} (arcsin (2 x) + arccos (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arcsin (2 x)) + \frac{d}{d x} (arccos (2 x))

\frac{d}{d x} (arcsin (2 x)) = \frac{2}{1 - 4 x ^{2}}

\frac{d}{d x} (arccos (2 x)) = - \frac{2}{1 - 4 x ^{2}}

= \frac{2}{1 - 4 x ^{2}} - \frac{2}{1 - 4 x ^{2}}

Vereinfache

= 0

y^{^{''}} - y^{^{'}} - 6 y = 2 e^{2 t} - t^{2} - 2 t + 3

x \to 6 lim (\frac{x ^{2} + 2 x - 48}{3 x ^{2} - 20 x + 12})

s im pl i f y \frac{- ln ( 1 + 6 x )}{x}

\frac{d}{d x} (ln (x^{2} + x + 1))

im pl i c i t 3 x^{3} + 2 y^{3} = 12