What is the tangent of sqrt(5x+6),\at x=2 ?

The tangent of sqrt(5x+6),\at x=2 is y= 5/8 x+11/4

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tangent of sqrt(5x+6),\at x=2

tangent of

5 x + 6, at x = 2

y = \frac{5}{8} x + \frac{11}{4}

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

y = 5 x + 6 : \frac{d y}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

y = 5 x + 6

x = 2 : m = \frac{5}{8}

Find the line with slope m=

\frac{5}{8}

and passing through

(2, 4) : y = \frac{5}{8} x + \frac{11}{4}

y = \frac{5}{8} x + \frac{11}{4}

y = e^{3 x}, at x = \frac{1}{3} ln (3)

y (x + 1) + \frac{d y}{d x} = 0

6 - x^{2}

\int_{- y}^{y} x d x

\frac{d}{d x} (2 x e^{- 3 x})

What is the tangent of sqrt(5x+6),\at x=2 ?
The tangent of sqrt(5x+6),\at x=2 is y= 5/8 x+11/4