What is the integral from-2 to 3 of \sqrt[3]{x} ?

The integral from-2 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3})/4-3/(2^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 3 of \sqrt[3]{x}

Decimal Notation

1.35517 \dots

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{3}

= [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{3}

Compute the boundaries:

\int x^{3} x^{2} - 2 d x

y^{^{'}} + \frac{1}{2} y = x

\int_{0}^{1} 4 x^{2} + 1 d x

\int \frac{6}{3 sin ( x ) - 4 cos ( x )} d x

\int \frac{2}{x ^{2}} - \frac{x ^{2}}{2} d x

What is the integral from-2 to 3 of \sqrt[3]{x} ?
The integral from-2 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3})/4-3/(2^{2/3)}