derivative of x^2+2x-1

解答

\frac{d}{d x} (x^{2} + 2 x - 1)

2 x + 2

求解步骤

\frac{d}{d x} (x^{2} + 2 x - 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x + 2 - 0

化简

= 2 x + 2

- 4 \frac{d y}{d x} + 12 x^{2} = 0

d er i v a t i v e y = 2 x - 3

a re a y = x + 6, y = x^{3}, x = 0

\frac{d}{d x} (a^{- x})

\frac{d}{d t} (3 t + 1)