derivative of sin^2(2x+5)

解答

\frac{d}{d x} (sin^{2} (2 x + 5))

4 sin (2 x + 5) cos (2 x + 5)

求解步骤

\frac{d}{d x} (sin^{2} (2 x + 5))

使用连锁律:

2 sin (2 x + 5) \frac{d}{d x} (sin (2 x + 5))

= 2 sin (2 x + 5) \frac{d}{d x} (sin (2 x + 5))

\frac{d}{d x} (sin (2 x + 5)) = cos (2 x + 5) \cdot 2

= 2 sin (2 x + 5) cos (2 x + 5) \cdot 2

化简

= 4 sin (2 x + 5) cos (2 x + 5)

\frac{d}{d x} ((\frac{x - 7}{x + 2})^{3})

\int \frac{1}{x - 3 3 x} d x

d er i v a t i v e y = \frac{8 - x e ^{x}}{x + e ^{x}}

\frac{\partial}{\partial x} (\frac{2 F ( V , x , P )}{V ^{2} x P})

\frac{d ^{3}}{d x ^{3}} (\frac{5}{x})