What is the derivative of tan(5x+2) ?

The derivative of tan(5x+2) is sec^2(5x+2)*5

What is the first derivative of tan(5x+2) ?

The first derivative of tan(5x+2) is sec^2(5x+2)*5

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\frac{d}{d x} (tan (5 x + 2))

sec^{2} (5 x + 2) \cdot 5

Solution steps

\frac{d}{d x} (tan (5 x + 2))

Apply the chain rule:

sec^{2} (5 x + 2) \frac{d}{d x} (5 x + 2)

= sec^{2} (5 x + 2) \frac{d}{d x} (5 x + 2)

\frac{d}{d x} (5 x + 2) = 5

= sec^{2} (5 x + 2) \cdot 5

\frac{d}{d x} (x^{3} \cdot e^{- x})

\frac{d}{d x} (x^{4} - 8 x^{3} + 22 x^{2} - 24 x + 9)

x^{4} + x y^{2} = 5, (1, 2)

\frac{d}{d x} (4 x - \frac{2}{x ^{3}})

\frac{\partial}{\partial x} (\frac{x}{x + y} + e^{x y} x + 4 y)

What is the derivative of tan(5x+2) ?
The derivative of tan(5x+2) is sec^2(5x+2)*5
What is the first derivative of tan(5x+2) ?
The first derivative of tan(5x+2) is sec^2(5x+2)*5