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Popular >

(y^2+yx)dx+x^2dy=0

Solution

(y^{2} + y x) d x + x^{2} d y = 0

Solution

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

Solution steps

(y^{2} + y x) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

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y = 2 x + 8

Frequently Asked Questions (FAQ)

What is the solution for (y^2+yx)dx+x^2dy=0 ?
The solution for (y^2+yx)dx+x^2dy=0 is y=(2x)/(-1+2c_{1)x^2}