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人気のある微分積分 >

sum from n=1 to infinity of nsin(npi)

解

n = 1 \sum \infty n sin (nπ)

解

0

解答ステップ

n = 1 \sum \infty n sin (nπ)

n sin (nπ) = 0

= n = 1 \sum \infty 0

\sum 0 = 0

= 0

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