What is the derivative of x+log_{e}(x) ?

The derivative of x+log_{e}(x) is 1+1/x

What is the first derivative of x+log_{e}(x) ?

The first derivative of x+log_{e}(x) is 1+1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x + lo g_{e} (x))

1 + \frac{1}{x}

Solution steps

\frac{d}{d x} (x + lo g_{e} (x))

Simplify

x + lo g_{e} (x) : x + ln (x)

= \frac{d}{d x} (x + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (ln (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 1 + \frac{1}{x}

x^{2} - x

\frac{d x}{d t} - 4 x = cos (5 t)

f (x) = - 3 x^{3} - 2 x^{2} - x + 3, (-, 5)

n = 1 \sum \infty \frac{1}{n ^{7}}

\int sin (12 x) cos (9 x) d x

What is the derivative of x+log_{e}(x) ?
The derivative of x+log_{e}(x) is 1+1/x
What is the first derivative of x+log_{e}(x) ?
The first derivative of x+log_{e}(x) is 1+1/x