What is the derivative of 2x-2sin(x) ?

The derivative of 2x-2sin(x) is 2-2cos(x)

What is the first derivative of 2x-2sin(x) ?

The first derivative of 2x-2sin(x) is 2-2cos(x)

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\frac{d}{d x} (2 x - 2 sin (x))

2 - 2 cos (x)

Solution steps

\frac{d}{d x} (2 x - 2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (2 sin (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

= 2 - 2 cos (x)

f (x) = x^{4} + 8 x^{2} - x, (1, 8)

\frac{d}{d x} (y e^{x y})

\int_{0}^{2} \frac{1}{2 - x} d x

\int (sin (x))^{- 1} d x

- x, x - x^{2}, 0, 2

What is the derivative of 2x-2sin(x) ?
The derivative of 2x-2sin(x) is 2-2cos(x)
What is the first derivative of 2x-2sin(x) ?
The first derivative of 2x-2sin(x) is 2-2cos(x)