What is the derivative of ln(w(h-l)+pi-T)+ln(l) ?

The derivative of ln(w(h-l)+pi-T)+ln(l) is (h-l)/(w(h-l)+pi-T)

What is the first derivative of ln(w(h-l)+pi-T)+ln(l) ?

The first derivative of ln(w(h-l)+pi-T)+ln(l) is (h-l)/(w(h-l)+pi-T)

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derivative of

ln (w (h - l) + π - T) + ln (l)

\frac{h - l}{w ( h - l ) + π - T}

Solution steps

\frac{d}{d w} (ln (w (h - l) + π - T) + ln (l))

Simplify

ln (w (h - l) + π - T) + ln (l) : ln (l (w (h - l) + π - T))

= \frac{d}{d w} (ln (l (w (h - l) + π - T)))

Treat

l, h, T

as constants

Apply the chain rule:

\frac{1}{l ( w ( h - l ) + π - T )} \frac{d}{d w} (l (w (h - l) + π - T))

= \frac{1}{l ( w ( h - l ) + π - T )} \frac{d}{d w} (l (w (h - l) + π - T))

\frac{d}{d w} (l (w (h - l) + π - T)) = l (h - l)

= \frac{1}{l ( w ( h - l ) + π - T )} l (h - l)

Simplify

\frac{1}{l ( w ( h - l ) + π - T )} l (h - l) : \frac{h - l}{w ( h - l ) + π - T}

= \frac{h - l}{w ( h - l ) + π - T}

\frac{\partial}{\partial x} (x^{2} + 3 x y)

y = \frac{x}{6} - \frac{6}{x}

\frac{\partial}{\partial x} (- 0.1 \cdot cos (6 \cdot x))

x \to 0 lim (\frac{- 11 x ^{2} + 9 x}{x})

\int x sin (3 + 3 x) d x

What is the derivative of ln(w(h-l)+pi-T)+ln(l) ?
The derivative of ln(w(h-l)+pi-T)+ln(l) is (h-l)/(w(h-l)+pi-T)
What is the first derivative of ln(w(h-l)+pi-T)+ln(l) ?
The first derivative of ln(w(h-l)+pi-T)+ln(l) is (h-l)/(w(h-l)+pi-T)