What is the derivative of (-9/(\sqrt[4]{x)}) ?

The derivative of (-9/(\sqrt[4]{x)}) is 9/(4x^{5/4)}

What is the first derivative of (-9/(\sqrt[4]{x)}) ?

The first derivative of (-9/(\sqrt[4]{x)}) is 9/(4x^{5/4)}

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\frac{9}{4 x ^{\frac{5}{4}}}

Solution steps

Simplify

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 9 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 9 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

- 9 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : \frac{9}{4 x ^{\frac{5}{4}}}

= \frac{9}{4 x ^{\frac{5}{4}}}

\frac{d}{d x} (ln (\frac{x - 2}{x + 1}))

\int (2 - x)^{2} ln (4 x) d x

\frac{11}{3} t^{3} + 11 t^{2}

\frac{d}{d x} ((6 x^{2} + 6) e^{- x})

\frac{d}{d x} (e^{l n (2)})

What is the derivative of (-9/(\sqrt[4]{x)}) ?
The derivative of (-9/(\sqrt[4]{x)}) is 9/(4x^{5/4)}
What is the first derivative of (-9/(\sqrt[4]{x)}) ?
The first derivative of (-9/(\sqrt[4]{x)}) is 9/(4x^{5/4)}