What is (\partial)/(\partial x)(4e^{x^7y}) ?

The answer to (\partial)/(\partial x)(4e^{x^7y}) is 28e^{x^7y}x^6y

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(\partial)/(\partial x)(4e^{x^7y})

\frac{\partial}{\partial x} (4 e^{x^{7} y})

28 e^{x^{7} y} x^{6} y

Solution steps

\frac{\partial}{\partial x} (4 e^{x^{7} y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (e^{x^{7} y})

Apply the chain rule:

e^{x^{7} y} \frac{\partial}{\partial x} (x^{7} y)

= e^{x^{7} y} \frac{\partial}{\partial x} (x^{7} y)

\frac{\partial}{\partial x} (x^{7} y) = 7 y x^{6}

= 4 e^{x^{7} y} \cdot 7 y x^{6}

Simplify

= 28 e^{x^{7} y} x^{6} y

\int x^{2} - 4 x + 29 d x

\frac{d}{d x} ((1 + x)^{2} ln (1 + x))

y^{10} y^{^{'}} = 13 cos (π x)

\int 7 - 3 (1 + x^{2})^{- 1} d x

6 x^{^{''}} + 1960 x = 0, x (0) = - 3, x^{^{'}} (0) = 0

What is (\partial)/(\partial x)(4e^{x^7y}) ?
The answer to (\partial)/(\partial x)(4e^{x^7y}) is 28e^{x^7y}x^6y