What is the integral from 0 to infinity of 4e^{-x} ?

The integral from 0 to infinity of 4e^{-x} is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of 4e^{-x}

\int_{0}^{\infty} 4 e^{- x} d x

4

Solution steps

\int_{0}^{\infty} 4 e^{- x} d x

Compute the indefinite integral:

\int 4 e^{- x} d x = - 4 e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} 4 e^{- x} d x = 0 - (- 4)

= 0 - (- 4)

Simplify

= 4

\int (\frac{x}{2 x + 1}) d x

\frac{d}{d x} (- 5^{8 x^{2} - 1})

\int 10 sin^{4} (x co) s^{2} x d x

3 x - 5 x^{2}

\frac{\partial}{\partial x} (e^{∣ x yz ∣})

What is the integral from 0 to infinity of 4e^{-x} ?
The integral from 0 to infinity of 4e^{-x} is 4