What is the integral of (1-x)^{1/2} ?

The integral of (1-x)^{1/2} is -2/3 (1-x)^{3/2}+C

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integral of (1-x)^{1/2}

\int (1 - x)^{\frac{1}{2}} d x

- \frac{2}{3} (1 - x)^{\frac{3}{2}} + C

Solution steps

\int (1 - x)^{\frac{1}{2}} d x

Apply u-substitution

: \int - u^{\frac{1}{2}} d u

= \int - u^{\frac{1}{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{\frac{1}{2}} d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= - \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 1 - x

= - \frac{2}{3} (1 - x)^{\frac{3}{2}}

Add a constant to the solution

= - \frac{2}{3} (1 - x)^{\frac{3}{2}} + C

\int 9 x (9 - x^{- 4}) d x

x \to 3 - lim (\frac{x - 3}{x ^{2} - 9})

y = (x^{3} - 25 x)^{12}, (5, 0)

\int x sin (d) x d x

x \to \frac{π}{4} lim (sec (x))

What is the integral of (1-x)^{1/2} ?
The integral of (1-x)^{1/2} is -2/3 (1-x)^{3/2}+C